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4,407 questions JAMB 2359 WAEC 1853 NECO 179 POST_UTME 6 CUSTOM 10

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4,407 questions

Question 1 of 20 4,407 total questions

Question 2101

jamb 1982

A man bought wrist watch for N150 but was only able to sell it for N120. Find the loss per cent on the transaction

A25%

B11%

C20%

D80%

E30%

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Question 2102

jamb 1982

What is the least possible value of \(\frac{9}{1 + 2x^2}\) if 0 \(\geq\) x \(\geq\) 2?

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Question 2103

jamb 1982

Which of the following lines is not parallel to the line 3y + 2x + 7 = 0?

A3y + 2x - 7 = 0

B9y + 6x + 17 = 0

C24y + 16x + 19 = 0

D3y - 2x + 7 = 0

E15y + 10x - 13 = 0

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Question 2104

jamb 1982

Find \(\alpha\) and \(\beta\) such that x\(\frac{3}{8}\) x y\(\frac{-6}{7}\) x (\(\frac{y^{\frac{9}{7}}}{x^{\frac{45}{8}}}\))\(\frac{1}{9}\) = \(\frac{x^{\alpha}}{y^{\beta}}\)

A\(\alpha\) = 1, \(\beta\) = \(\frac{5}{7}\)

B\(\alpha\)= 1, \(\beta\) = -\(\frac{5}{7}\)

C\(\alpha\)= \(\frac{3}{5}\), \(\beta\) = -6

D\(\alpha\)= 1, \(\beta\) = -\(\frac{3}{5}\)

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Question 2105

jamb 1982

Write the equation 2 log2x - x log2(1 + y) = 3 in a form not involving logarithms

A2^x(1 + y) = 3

B2^x - x(1 + y) = 8

Cx² = 8(1 + y)^x

Dx² - x(1 + y) = 8

Ex² - (1 + y)² = 8

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Question 2106

jamb 1982

The graphical method of solving the equation x3 + 3x2 + 4x - 28 = 0 is by drawing the graphs of the curves

Ay = x³ and y = 3x² + x - 28

By = x³ + 3x² + 4x + 4 and the line y = \(\frac{28}{x}\)

Cy = x³ + 3x² + 4x and y

Dy = x² + 3x + 4 and y = \(\frac{28}{x}\)

Ey = x² + 3x + 4 and line y = 28x

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Question 2107

jamb 1982

The solution of the quadratic equation bx\(^2\) + cx + a = 0 is given by

Ax = b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2a}\)

Bx = c \(\pm\) \(\frac{\sqrt{b^2 - 4ab}}{2b}\)

Cx = -c \(\pm\) \(\frac{\sqrt{c^2 - 4ab}}{2b}\)

Dx = -b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2b}\)

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Question 2108

jamb 1982

The factors of 6x - 5 - x2 are

A-(x + 3)(x + 2)

B(x + 5)(x + 1)

C(x - 5)(1 - x)

D(x + 1)(x + 5)

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Question 2109

jamb 1982

Seven years ago, the age of a father was three times that of his son, but in six years time the age of the son will be half that of his father, representing the present ages of the father and son by x and y, respectively, the two equations relating x and y are

A3y - x = 0; 2y - x = 0

B3y - x = 14; x - 2y = 6

C3y - x =7; x - 2y = 6

D3y - x = 14; y - 2x = 6

Ex + 3y = 7; x = 2y = 12

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Question 2110

jamb 1982

If N560.70 is shared in the ratio 7 : 2 : 1, what is the smallest share?

AN392.49

BN56.70

CN113.40

DN112.14

EN56.07

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Question 2111

jamb 1982

Simplify 3 - 2 \(\div\) \(\frac{4}{5}\) + \(\frac{1}{2}\)

A1\(\frac{3}{4}\)

B-1

C1\(\frac{3}{10}\)

E1\(\frac{9}{10}\)

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Question 2112

jamb 1982

Rationalize the expression \(\frac{1}{\sqrt{2} + \sqrt{5}}\)

A\(\frac{1}{3}\)(\(\sqrt{5} - \sqrt{2}\)

B\(\frac{\sqrt{2}}{3}\) + \(\frac{\sqrt{5}}{5}\)

C\(\sqrt{2} - \sqrt{5}\)

D5(\(\sqrt{2} - \sqrt{5}\)

E\(\frac{1}{3}\)(\(\sqrt{2} - \sqrt{5}\)

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Question 2113

jamb 1981

In the figure, WU//YZ, WY//VU = 12cm, VZ = 6cm, XU = 8cm. Determine the length of WU.

A1cm

B6cm

C2cm

D4cm

E3cm

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Question 2114

jamb 1981

In the diagram, XZ is the diameter of a circle's radius \(\frac{5}{2}\). If XY is 4cm, then the area of the triangle XYZ is

A12cm²

B28\(\frac{1}{2}\)cm²

C16cm²

D10cm²

E6cm²

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Question 2115

jamb 1981

In the figure, find x in terms of a, b and c.

Aa + b + c

B180^o - (a + b + c)

Ca - b - c

Da + b

Ea + c

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Question 2116

jamb 1981

In the figure, find the area of XYZW

A60cm²

B54cm²

C27cm²

D54\(\sqrt{2}\)cm²

E27\(\sqrt{2}\)cm²

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Question 2117

jamb 1981

In the figure, the chords XY and ZW are produced to meet at T such that YT = WT, ZYW = 40o and YTW = 30o. What is YXW?

A50^o

B75^o

C35^o

D115^o

E30^o

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Question 2118

jamb 1981

What is the length of an arc of a circle that subtends 2\(\frac{1}{2}\) radians at the centre when the radius of the circle is 8cm?

A8cm

B10cm

C40cm

D20cm

E16cm

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Question 2119

jamb 1981

Solve the given equation \((\log_{3} x)^{2} - 6(\log_{3} x) + 9 = 0\)

A27

C\(\frac{1}{27}\)

D18

E81

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Question 2120

jamb 1981

The sum of the root of a quadratic equation is \(\frac{5}{2}\) and the product of its root is 4. The quadratic equation is

Ax + 8x² - 5 = 0

B2x² - 5x + 8 = 0

C2x² - 8x + 5 = 0

Dx² + 8x - 5 = 0

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